Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

🧠 Explanation (Math):

Given: 3 consecutive odds $n,n+2,n+4$; $3n=2(n+4)+3$
Step 1: $3n=2n+8+3Rightarrow n=11$.
Step 2: Third $=n+4=15$.
Final Answer: 15