An observer 1.6m tall is 20√3m away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of the tower is:

🧠 Explanation (Math):

Given: Observer eye height = 1.6 m; horizontal distance = 20√3 m; elevation = 30°
Step 1: Vertical rise from eye to top = tan30° × 20√3 = (1/√3) × 20√3 = 20 m
Step 2: Tower height = eye level + rise = 1.6 + 20 = 21.6 m
Final Answer: 21.6 m