Find the value of x in the series: 3, 9, 25, 49, 81, 121

🧠 Explanation:

Given series = 3, 9, 25, 49, 81, 121

Second term = 9 = 3²

Third term = 25 = 5²

Fourth term = 49 = 7²

Fifth term = 81 = 9²

Sixth term = 121 = 11²

So from 2nd term onward pattern is perfect squares of odd numbers

First term = 3

Nearest square = 2² = 4

So we write first term as 2² − x = 3

⇒ 4 − x = 3

⇒ x = 1

Final Answer = 1